Imagine that the amount of bacteria in a petri dish grows exponentially through time, doubling every day until the dish is completely covered by bacteria on day 100. On what day would the petri dish be 50% covered by bacteria?

Correct  50% will be on day  99

Step-by-step explanation:

Given:

- amount of bacteria is doubling every day

- on day 100 amount is 100%

- on day n = ? will be 50%

We define the initial amount of bacteria with A

First day  -  A₁ = A · 2

Second day - A₂ = (A · 2) · 2 = A · 2²

Third day - A₃ = A₂ · 2 = A · 2³

n-th day   Aₙ = A · 2ⁿ

on day 100   A₁₀₀ = A · 2¹⁰⁰   -  100%

on day  n     Aₙ = A · 2ⁿ         -    50%

A₁₀₀ : Aₙ = A · 2¹⁰⁰ : A · 2ⁿ =  100% : 50% = 2 : 1

(A · 2¹⁰⁰) :  (A · 2ⁿ)  = 2 : 1   ⇒ A · 2ⁿ  = (A · 2¹⁰⁰) / 2 ⇒

2ⁿ  = 2¹⁰⁰ / 2¹ = 2⁹⁹ ⇒ 2ⁿ  = 2⁹⁹ ⇒ n = 99

n = 99

This problem could have been solved more simply. If we know that the quantity increases double every day, it is logical if 99 days is 50% that on the 100th day it will be double or 100%

God is with you!!!

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

they disappear if your absent from to long. i found out that the hard way.

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