A video rental company offers a plan that includes a membership fee of $9 and charges $1 for every DVD borrowed. They also offer a second plan, that costs $44 per month for unlimited DVD rentals. If a customer borrows enough DVDs in a month, the two plans cost the same amount. What is that total cost of either plan? How many DVDs is that? Each option costs $ if a customer rents DVDs.

A. $44

B. 35 DVD

Step-by-step explanation:

In this question, we have two different rental plans and we are asked to calculate the number of dvd rented in the first plan if the both resulted in the same amount.

Let’s answer the first question.

We are told to calculate the total cost of either plan.

From the question, we can see that the maximum amount to pay is $44 for the second plan and we are told that the first plan was equal to the second plan as some amount of dvd was rented.

The total cost of either plan is thus $44.

Let’s answer the second.

The first plan charged membership fee of $9 and rental fee of $1 per dvd. Since total cost here is $44, we have the following;

Let the number of DVD rented be n

9 + 1(n) = 44

9 + n = 44

n = 44-9

n = 35

This means that a total of 35 DVD were rented

answer: true

step-by-step explanation:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.