Mathematics, 07.04.2020 20:00 zookieblu
The dimensions of a chocolate box are: height = x+2 inches, length = 2x+5 inches, and width = 4x-1 inches. if the volume of the box is 605 cubic inches, what is the value of x?
I'm a bit stuck on this, so any help is appreciated. The work I have is:
(2x+5)*(4x-1)*(x+2) = 605
(8x^2 + 20x ā 2x ā 5) * (x + 2)
(8x^3 + 20x^2 ā 2x^2 ā 5x) + (16x^2 + 40x ā 4x ā 10)
Regroup
8x^3 + (20x^2 ā 2x^2 + 16x^2) + (40x ā 5x ā 4x) ā 10
8x^3 + 34x^2 + 31x ā 10 = 605
+10 +10
8x^3 + 34x^2 + 31x = 615
42x^5 + 31x = 615
73x^6 = 615
But I'm not exactly sure about it.
Answers: 3
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