If f(x)= (3/x) + 2- sqrt (x-3), complete the following statement: the domain for f(x) is all real numbers than or equal to 3.

The domain of the function is the set of all the values of x that would allow the function to have real values. Since the radicand is x - 3, the value of x cannot be less than 3 because that would make the value of sqrt (x - 3) an imaginary number. Thus, the domain should be all numbers GREATER than or equal to 3.