Mathematics, 14.04.2020 01:41 irisprats

Graph the six terms of a finite sequence where a1 = −6.25 and r = 1.25.

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Answer from: boo2023

The first of the sequence is -6.25.

The second term of the sequence is -7.81.

The third term of the sequence is -9.81.

The fourth term of the sequence is -12.20.

The fifth term of the sequence is -15.25.

The sixth term of the sequence is -19.07.

We have to determine, the six terms of a finite sequence and graph these terms.

According to the question,

The first term of the sequence = -6.25

And the common ratio is = 1.25

The six terms of finite sequence would be as per the following equation is determined by the formula,

$\rm f(x)= a_1 \times r^ {(n-1)}$

1. The first of the sequence is -6.25.

2. The second term of the sequence is,

$\rm a_2=(-6.25) \times (1.25)^ {(2-1)}\\\\a_2 = (-6.25) \times 1.25\\\\a_2 = -7.81$

The second term of the sequence is -7.81.

3. The third term of the sequence is,

$\rm a_3=(-6.25) \times (1.25)^ {(3-1)}\\\\a_3 = (-6.25) \times (1.25)^2\\\\ a_3 = (-6.25) \times 1.56\\\\a_3 = -9.81$

The third term of the sequence is -9.81.

4. The fourth term of the sequence is,

$\rm a_4=(-6.25) \times (1.25)^ {(4-1)}\\\\a_4= (-6.25) \times (1.25)^3\\\\ a_4 = (-6.25) \times 1.95\\\\a_4 = -12.20$

The fourth term of the sequence is -12.20.

5. The fifth term of the sequence is,

$\rm a_5=(-6.25) \times (1.25)^ {(5-1)}\\\\a_5= (-6.25) \times (1.25)^4\\\\ a_5 = (-6.25) \times 2.44\\\\a_5= -15.25$

The fifth term of the sequence is -15.25.

6. The sixth term of the sequence is,

$\rm a_6=(-6.25) \times (1.25)^ {(6-1)}\\\\a_6= (-6.25) \times (1.25)^5\\\\ a_6 = (-6.25) \times 3.05\\\\a_6= -19.07$

The sixth term of the sequence is -19.07.

For more details refer to the link given below.

link

Graph the six terms of a finite sequence where a1 = −6.25 and r = 1.25.

Answer from: jamilecalderonpalaci

Step-by-step explanation:

As per the question statement, a₁ is -6.25 and common ratio (r) is 1.25.

Therefore, the six terms of finite sequence would be as per the following equation $f(n) = a1(r)^{n-1}$ . Thus, the series would be

a1 = -6.25a2 = -6.25*r = -6.25*(1.25) = -7.8125a3 = -6.25*r^2 = -6.25*(1.25)^2 = -9.765625a4 = -6.25*r^3 = -6.25*(1.25)^3 = -12.20703125a5 = -6.25*r^4 = -6.25*(1.25)^4 = -15.2587890625a6 = -6.25*r^5 = -6.25*(1.25)^5 = -19.073486328125

So the points on the graph will be on following points,

(1, -6.25), (2, -7.8125), (3, -9.765625), (4, -12.20703125), (5, -15.2587890625), (6, -19.073486328125).

The graph would look like as attached.

Answer from: Quest

step-by-step explanation:

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Answer from: Quest

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