Mathematics, 14.04.2020 17:48 joshtassler15

Paul, who is standing 150 feet above the water on a balcony of a cruise ship,
sees two boats located due north. The angles of depression from Paul
to the boats are 33
and 22°
Find the distance between the two boats to the nearest tenth of a foot.

Answers: 1

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Paul, who is standing 150 feet above the water on a balcony of a cruise ship,
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Paul, who is standing 150 feet above the water on a balcony of a cruise ship, sees two boats located due north. The angles of depression from Paul to the boats are 33 and 22° Find the distance between the two boats to the nearest tenth of a foot.

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Another question on Mathematics

Paul, who is standing 150 feet above the water on a balcony of a cruise ship,
sees two boats located due north. The angles of depression from Paul
to the boats are 33
and 22°
Find the distance between the two boats to the nearest tenth of a foot.