Problem 2 (20 pts) A three-sigma fraction nonconforming control chart with center line 0.15, UCL = 0.27, and LCL = 0.03 is used to control a process. The sub-sample size for all samples is the same (fixed subsample size). (a) (5pts) Find the sub-sample size for the used p-chart (round the number). (b) (5pts) Find the probability of type I error (Use the Poisson approximation). 5 (c) (5pts) Find the probability of type II error if the process fraction defective is actually p = 0.25 (Use the Poisson approximation). (d) (5pts) Find ARL0 and ARL1 for p = 0.25

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

it is impossible.