There are 100 men and 100 seats, and each person has a pre-assigned seat. However, the first person is randomly assigned (either his/her seat or others). The rest people will either sit on his/her assigned seat if his/her seat is empty or randomly sit on another seat if his/her seat is occupied. What is the probability of the last person getting his/her pre-assigned seat?

1 / 2

Step-by-step explanation:

- First observe that the fate of the last person is determined the moment either the first or the last seat is selected! This is because the last person will either get the first seat or the last seat. Any other seat will necessarily be taken by the time the last guy gets to 'choose'.

- Since at each choice step, the first or last is equally probable to be taken, the last person will get either the first or last with equal probability: 1/2

- Armed with the key observation, we see that the event that the last person's correct seat is free, is exactly the same as the event that the first person's seat was taken before the last person's seat.

- Well, each person had to make a random choice, was equally likely to choose the first person's seat or the last person's seat - the random chooser exhibits absolutely no preference towards a particular seat. This means that the probability that one seat is taken before the other must be 1/2

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )