Which of the following equations represents the polynomial function with zeros 5, negative start fraction one over two end fraction, and −3, and a y-intercept of 15?

A. y = 2(x-5)(x+1/2)(x+3)
B. y = -(x+5)(2x-1)(x-3)
C. y = (x+5)(2x-1)(x-3)
D. y = -(x-5)(2x+1)(x+3)

  D.  y = -(x-5)(2x+1)(x+3)

Step-by-step explanation:

"r" is a zero of the polynomial when (x -r) is a factor.

The three given zeros mean that (x -5), (x -(-1/2)), and (x -(-3)) will be factors of the equation. The product of the constants in these binomials (and any vertical scale factor) must be equal to the y-intercept.

For some scale factor "a", we want ...

  (a)(-5)(1/2)(3) = 15

  a = 15/(-7.5) = -2

and the desired polynomial function is ...

  y = -2(x -5)(x +1/2)(x +3 = -(x -5)(2x +1)(x +3) . . . . matches choice D

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Comment on the answer choices

It's all about the details. The various answer choices differ in various signs, so you need to pay attention.

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12