A student does an experiment for a science fair to study whether temperature affects the timing of a cricket's chirps. The
student keeps a cricket in an enclosed box that is heated to different temperatures each day for twelve days. The student
records the cricket's chirps by using a sound-activated microphone so that the timing of the chirps can be measured. The
student records the results of the experiment in the table below
1
2
22
2.6
Day
Temperature (°C)
Average time between
chirps (sec)
3
| 23
2.2
|
4
24
2.3
6
26
5
| 25
2.0
7
27
1.9
8
28
1.8
9
29
1.4
10
30
1.2
11
31
1.5
12
32
1.1
2.5
1.8
Which conclusion can be made from the data in the table?
O The higher the temperature, the fewer chirps there will be in 10 seconds
O The chirps occur closer together as the temperature increases.
O The chirps become farther apart as the temperature increases
There is no relationship between temperature and the time between chirps.

36 girls

step-by-step explanation:

the 48 boys is 4 parts of the ratio

divide 48 by 4 to obtain one part of the ratio

= 12 ← 1 part of the ratio

3 parts = 3 × 12 = 36 ← number of girls

id

step-by-step explanation:

idk

idk

i know the way

and

idk

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

-1/4 > -1 2/3. -1/4 is greater than -1 2/3 because it is closer to 0 on the number line.