A flowerpot has a circular base with a diameter of 27 centimeters find the circumference of the base of the flowerpot round to the nearest tenth

The answer to your question is 84.8 cm

Step-by-step explanation:

Data

diameter = 27 cm

π = 3.14

circumference = ?

Process

To find the circumference of the flowerpot just find the radius and substitute the values in the formula.

1.- Find the radius

radius = diameter / 2

-Substitution

radius = 27/2 = 13.5 cm

2.- Formula

Circumference = 2πr

-Substitution

Circumference = 2(3.14)(13.5)

-Simplification

Circumference = 84.78 cm ≈ 84.8 cm

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

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