Need help on 3/4 please help me fast please read it and help me

Step-by-step explanation:

3) ΔABC ≅ ΔDEF

AB = ED   {Corresponding parts of corresponding  triangles are equal}

6y - 4 = 4y +2

add 4 to both sides

6y - 4 + 4 = 4y + 2 + 4

6y = 4y + 6

subtract 4y from both sides

6y - 4y = 4y + 6 - 4y

2y = 6

Divide by 2

y = 3

AB = 6y - 4 = 6*3 - 4 = 18 - 4 =14

AB = 14

ΔABC ≅ ΔDEF

∠A = ∠D   {Corresponding parts of corresponding  triangles are equal}

5x + 2 =87

5x = 87 - 2

5x = 85

x = 85/5

x = 17

In ΔDEF,

∠D + ∠E + ∠F = 180°   {SUM OF ALL ANGLES OF TRIANGLES}

87 +  42 + ∠F = 180  

129 + ∠F = 180°

∠F = 180 - 129

∠F =  51°

ΔABC ≅ ΔDEF

∠C = ∠F   {Corresponding parts of corresponding  triangles are equal}

3y = 51

y= 51/3

y = 17

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

ok

step-by-step explanation: