7. A rock is thrown with a height equation of h=-1612 20t 5 (where h is the height of the rock in feet at any given time of t in seconds). Will it reach a height of 30 feet? Explain your answer

There are no real solution to the equation when h = 35 ft.

Step-by-step explanation:

Here we have the equation for the height of the rock in ft given as

For the rock to reach 30 ft we must have

That is

or

From which it is observed that since the root of the equation is given by the quadratic formula

b² should be greater than 4·a·c  however

(-20)² (4×16×25)

Hence the equation has only imaginary roots.

i hope this is what you were looking for.

see attached graph

8.75

how-to:

first, we need to find what we have to work with.

since i know that we have 7 (years) and 0.8 (inches), we can use these to solve and find the equation!

secondly, what you want to do, is see that we need to know how much growth out of the 0.8 inches he got in only 1 year, instead of 7 years.

let's try to divide.

7 ÷ 0.8 = 8.75