Please help!
Two semicircles are placed in a rectangle. The width of the rectangle is 7 cm.

Find the area of the shaded region. Use the value 3.14 for pi , and do not round your answer.

Total length of the rectangle = 14+14= 28cm

width= 7 cm

Area of the rectangle = 28×7cm²

= 196 cm²

Area of 2 semicircles = Area of 1 circle

= π(7)² = 3.14×49= 153.86cm²

Area of the shaded region = 196-153.86

= 42.14 cm²

42.14

Step-by-step explanation:

Assuming that the width of the rectangle is 7 cm, the semi-circle's radius is also 7 cm.

Let's calculate the area of the two semi-circles, which in total makes a whole circle.

The formula for a circle is

Since r = 7, plug it in the formula:

Now, to figure out the length of the rectangle, look at the semi-circles. Their radius is 7 cm, so their diameter is 14 cm. We have two semi-circles with the diameter (14 cm), so we can say that the width is 28 cm.

Area of a rectangle:

To find the area of the shaded region, we subtract the area of the semi-circles to the rectangle, which should be:

salary

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.