Determine the critical values of f(x) = ax² + bx + c.
A critical value can occur where f'(x) = 0 and also where f'(x) does not exist. Since f'(x) is a polynomial, there are no x-values where f '(x) does not exist. Therefore, the only critical values will be where f'(x) = 0.
Solve the equation f'(x) = 0 for x.

  x = -b/(2a)

Step-by-step explanation:

Using the power rule for derivatives, you can find ...

  f'(x) = 2ax +b

Solving for x when f'(x) = 0, we have ...

  2ax +b = 0

  2ax = -b

  x = -b/(2a)

The critical value is x = -b/(2a).

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

goog may be able to you find that answer