You deposit $200 in an account earning 3.5% simple interest. How long will it take for the balance of the account to be $249? Write down the formulas you are going to use.

7 years

Step-by-step explanation:

Simple interest is given by

I = PRT where I is the interest, P is the principle r is the rate and t is time

If we have 249 in the account and started with 200,

the interest is 249-200 = 49

The principle is 200 and the rate is 3.5% or in decimal form .035

Putting into the equation

49 = 200 (.035) t

49 =7t

Divide each side by 7

49/7 = 7t/7

7 =t

It will take 7 years

7 years

Step-by-step explanation:

I = P×r×t

I = 249 - 200 = 49

49 = 200 × (3.5/100) × t

t = 49/7

t = 7

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2