A bag contains 5 yellow blocks, 2 green blocks and 3 blue blocks. If you choose one block and then another block without putting the first one back in the bag, what is the probability that the first block will be green and the second will be yellow

The probability that the first block will be green and the second will be yellow is    or 0.111.

Step-by-step explanation:

We are given that a bag contains 5 yellow blocks, 2 green blocks and 3 blue blocks.

Also, we choose one block and then another block without putting the first one back in the bag.

Firstly, as we know that Probability of any event is given by ;

           Probability of an event  =    

SO, Probability that the first block will be green =  

Here, Number of green blocks = 2

Total number of blocks in bag = 5 yellow + 2 green + 3 blue = 10 blocks

So, Probability that the first block will be green  =  

Similarly, Probability that the second block will be yellow =  

Here, Number of yellow blocks = 5

Total number of remaining blocks in bag = 10 - 1 = 9 blocks  {because we haven't put the block back after choosing the first}

So, Probability that the second block will be yellow  =  

Now, Probability that the first block will be green and the second will be yellow  =  

            =    = 0.111

Hence, the required probability is 0.111.

i dont get the question

step-by-step explanation:

it is definatly the 3rd one. very much looks like it, for a good chance, the third one would be best for you.

8(4)^8=72^feet to say that the total can conclude to 8(4) which as you know would mean 8 x 4. that equals 32w. 32^ could make a 72 answer as well. but your coefficent will remain w so your answer is 72w.

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