Three cards are drawn sequentially from a shuffled deck without replacement. What is the approximate probability all three drawn cards have NUMBERS on them?

Step-by-step explanation:

There are 36 numbered cards out of 52 total cards .

so in the first attempt probability of numbered cards being drawn

= 36 / 52

After first draw , numbered cards remaining = 35 , total no of card remaining = 51

probability of numbered card  in 2nd attempt = 35 / 51

Probability in third attempt

= 34 / 50

Total probability  of all cards being numbers = (36 / 52) x (35 / 51) x (34/50)

points are handed out whenever you post answers.

brainliest answers are handed out by the person asking the question, so whether your answer is picked depends entirely on whether the asker bothers to pick

if you're asking about your rank, it depends on having a certain number of points and a certain number of brainliest answers. for example, at the time of this writing, i have 44338 points out of 15000 needed for the next (nearly triple the requirement! ) but i only have 24 out of 50 required brainliest answers. this number decays, meaning after a certain amount of time (i think about a month), the total number of brainliest answers you've earned doesn't count toward this total. (i've been stuck at the same rank for a long

the lesson to learn here is that you shouldn't worry about points or rank. chances are, no matter how good an answer you may provide, your efforts will go mostly unnoticed unless you focus on the newest/most active questions that get posted.