Find the approximate volume of this prism.

A: 62 m3

B: 44 m3

C:72 m3

D: 108 m3

62m³

Step-by-step explanation:

The question is incomplete. Find the diagram of the prism attached below.

Volume of a Prism = Base area × Height

Given height = 9m

Since the prism is a triangular based prism,

Base area = area of the equilateral triangle = 1/2bh

base of the triangle = 4m

Height can be gotten using Pythagoras theorem.

Slant side of the triangle is the hypotenuse = 4m

Adjacent = 1/2 of the base = 1/2(4)= 2m

Height = √4²-2²

Height = √16-4

Height of the triangle= √12 m

Base Area = 1/2×4×√12

Base Area = 2√12 m

Volume of the prism = 2√12 × 9

= 2×2√3×9

= 36√3 m³

= 62.2m³

Volume of the prism is approximately 62m³

what the question so we can you out

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841