Rachel is a financial investor who actively buys and sells in the securities market. Now she has a portfolio of all blue chips, including: $13,500 of Share A, $7,600 of Share B, $14,700 of Share C, and $5,500 of Share D. Required: a) Compute the weights of the assets in Rachel’s portfolio? (2 marks) b) If Rachel’s portfolio has provided her with returns of 9.7%, 12.4%, -5.5% and 17.2% over the past four years, respectively, calculate the geometric average return of the portfolio for this period. (2 marks) c) Assume that expected return of the stock A in Rachel’s portfolio is 13.6% this year. The risk premium on the stocks of the same industry are 4.8%, betas of these stocks is 1.5 and the inflation rate was 2.7%. Calculate the risk-free rate of return using Capital Market Asset Pricing Model (CAPM). (2 marks) d) Following is forecast for economic situation and Rachel’s portfolio returns next year, calculate the expected return, variance and standard deviation of the portfolio

Step-by-step explanation:

a) Weights of assest in Rachel's portfolio: = amount in each stock/ sum of amounts invested in all stocks

Share Amount Weights

A 13500 0.33

B 7600 0.18

C 14700 0.36

D 5500 0.13

TOTAL: 41300

b) Geometric average return of a portfolio = ((1+R1)*(1+R2)*(1+R3)*(1+Rn))^(1/n) - 1

where, R1= return of period 1 Rn= return in nth period

Hence, Geometric average return of Rachel's portfolio=

((1+9.7%)*(1+12.4%)*(1-5.5%)*(1+17.2%))^(1/4) - 1

= 8.10 % (approx) per year.

c) Using nominal rate of return (including inflation)

CAPM: Required return= Risk free return + (Risk premium * Beta)

13.6 = Rf + (4.8*1.5)

hence, Rf= 6.4% (not inflation adjusted)

inflation adjusted rate of return: ((1+return)/(1+inflation rate))-1

= ((1+13.6%)/(1+2.7%))-1

= 10.61%

Using CAPM: 10.61= Rf + (4.8*1.5)

hence, Rf= 3.41% (at real rates)

In practice, using the inflation adjusted return (real rate of return), i.e, 10.61% is better because it puts forth a long term perspective as to how a stock is performing.

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation:

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.