A bag contains 4 red marbles, 3 blue marbles and 6 green marbles. If two marbles are
drawn out of the bag, what is the probability, to the nearest 100oth, that both
marbles drawn will be red?

Step-by-step explanation:Total marble = 4+6+7 = 17Number of green = 7Prob(1st green) = 7/17Now their are 6 green left and 16 marbleProb(2nd green) = 6/16 = 3/8Now their are 5 green left and 15 marbleProb(3rd green) = 5/15 = 1/3Prob(1st and 2nd and 3rd green) will be = 7/17 × 3/8 × 1/3= 7/(17×8)= 7/136.

Step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.