Square EFGH has vertices: E = (-1,1), F = (-1,2), G = (-2,1), H = (-2, 2). In which quadrant will the image of vertex E' be if the square is rotated 270° clockwise about the origin O? Quadrant I Quadrant II Quadrant III Quadrant IV

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

it would be a on edgenuit y

the diagram below is your final answer

you are having disney spells!

answer: the answer is 100 x 12,500, which is 1,250,000.

step-by-step explanation: emily solved for a part when she should have solved for the whole.  

875,000 should be the numerator of the equivalent ratio.  

70 x 12,500 is 875,000.