The base of a triangle exceeds the height by 7 centimeters . If the area is 114 square centimeters, find the length of the base and the hight of the triangle

base length = 19 cm  ,  height = 12 cm

Step-by-step explanation:

Area formula  :  A =  (1/2)*b*h

b = h + 7 cm

A = 114 sq. cm

114  =  (1/2) * (h + 7) *h

228 = hh + 7h

hh + 7h - 228 = 0

h = -7/2   +  root( 49 - 4*(-228)) /2

h = -7/2 + 31/2

h = 24/2 = 12 cm

base = 12 cm + 7 cm = 19 cm

there are no figures how am i supposed to answer this question

step-by-step explanation:

47 - 90 = 43

43 - 180 = x

x = 137