Use the table below to find the percentage of data items in a normal distribution that lie between z = 0 1 and 2 - 27
score 01 02 03 04 05 06 07 08 09 10
Percentile 53 98 57 93 61 79 65 54 69 15 72 57 75 80 78 81 81 59 84.13
score 11 12 13 14 15 16 17 18 19 20
Percentile 36 43 88 49 90 32 91 92 93 32 94 52 95 54 96 4197.13 97 72
2 score 21 22 23 24 25 26 27 28 29 30
Percentile 982198 61 98 9399 18 99 38 99 53 99 65 99 74 99 81 99 87
The percentage of data items in a normal distribution that lie between z = 0 1 and 2 - 27
%
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Evaluate 8x2 + 9x − 1 2x3 + 3x2 − 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 − 2x = x(2x2 + 3x − 2) = x(2x − 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the form† 8x2 + 9x − 1 x(2x − 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x − 1)(x + 2), obtaining 8x2 + 9x − 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x − 1).