Which equation describes a rational function with x-intercepts at-4 and 2, a vertical asymptote at x = 1 and x = -1, and a
horizontal asymptote at y = -3?
f(x) = -3(x-4)(x+2)
x - 1
x2 - 1
-3(x+4)(x-2)
f(x) =
-2
-3(x-4)(x+2)
fix) = -3(x + 4)(x - 2)

answer:

c. the third graph

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation:

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x