HA
Jin recorded the ages (in years) for a sample of 4 zebras from a wildlife preserve. Here are the ages:
2,9, 14, 15
The mean of these ages is 7 = 10 years.
What is the standard deviation?
Round your answer to two decimal places.
8,
years

5.94

Step-by-step explanation:

Given the following information:

Ages of 4 zebras from a wildlife

=> the sample mean of this date is

=

=

The standard deviation can be determined by using this formula:

<=>

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3