A cable provider wants to contact customers in a particular telephone exchange to see how satisfied they are with the new digital tv service the company has provided. all numbers are in the 174 exchange, so there are 10 comma 000 possible numbers from 174-0000 to 174-9999. if they select the numbers with equal probability: what is the probability the number selected will be an even number?

1/2 or 0.5

Step-by-step explanation:

To determine whether the numbers are odd or even, we must take note of the last digit of the number.

The number ranges from 174-0000 to 174-9999

So, the last digit ranges from 0 to 9.

For the number to be even, the last digit must be even or zero.

Possible last digit for even numbers are;

0,2,4,6,8

Making it 5 possible last digit for even numbers.

Possible last digit of all numbers are;

0,1,2,3,4,5,6,7,8,9

10 possible last digits.

the probability the number selected will be an even number;

P = number of even last digits/number of all possible last digits

P = 5/10

P = 1/2 = 0.5

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: 7

step-by-step explanation: