Mathematics, 24.05.2020 00:00 thedocgalloway
1. An object is propelled off of a platform that is 75 feet high at a speed of 45 feet per second (ft./s). The height of the object off the ground is given by the formula
h(t) =-16t^2+45t+75where h(t) is the object's height at time (t) seconds after the object is propelled. The downward negative pull on the object is represented by-16t^2
Solve for t.
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1. An object is propelled off of a platform that is 75 feet high at a speed of 45 feet per second (f...
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