Prove: The square of a number that is one more than a multiple of 3 is also one more than a multiple of 3

  3(3n² +2n) +1

Step-by-step explanation:

All you have to do is factor the greatest common (integer) factor from the two terms containing n

The greatest common factor of 3·3 = 9 and 3·2 = 6 is 3. That's what goes in the green box outside parentheses. Then the numbers inside parentheses are the remaining factors of those coefficients:

  3(3n² +2n) +1

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The fact that you're concerned with multiples of 3 is an additional clue that 3 is a factor of the product. So, the form you're looking for is 3( ) +1.

found it xd it ok yt

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.