What is the y coordinate of the center of the circle for the following equation? X squared plus y squared minus 10y plus 18x = 2

Center of the circle is (-9, -7)

Radius of the circle = 5 units

Given question is incomplete: here is the complete question.

Certain circle can be represented by the following equation. x^2+y^2+18x+14y+105=0.

What is the center of this circle ?

What is the radius of this circle ?

Since equation of the circle has been given by the equation,

x² + y² + 18x + 14y + 105 = 0

Now we will convert this equation to the standard form of the circle.

x² + 18x + y² + 14y = -105

[x² + 2(9)x] + [y² + 2(7)x] = -105

[x² + 2(9)x + 9²] + [y² + 2(7)y + 7²] = 9² + 7² - 105

(x + 9)² + (y + 7)² = 81 + 49 - 105

(x + 9)² + (y + 7)² = 25

(x + 9)² + (y + 7)² = 5²

By comparing this equation with the standard equation of the circle → (x - h)² + (y - k)² = r²

Center of the circle is (-9, -7) and radius of the circle is 5 units.

do i do it on a graph?

step-by-step explanation:

5+2x=a

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