Mathematics, 31.05.2020 03:58 xdimplesjoon

Substitute the value of x back into the equation x + 3 – 2x = negative 2 x equals negative StartFraction one-fourth EndFraction plus StartFraction one-half EndFraction x plus 5. + x + 5 to justify the solution. What value of x is the solution?

x =

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Substitute the value of x back into the equation x + 3 – 2x = negative 2 x equals negative StartFraction one-fourth EndFraction plus StartFraction one-half EndFraction x plus 5. + x + 5 to justify the solution. What value of x is the solution? x =

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Substitute the value of x back into the equation x + 3 – 2x = negative 2 x equals negative StartFraction one-fourth EndFraction plus StartFraction one-half EndFraction x plus 5. + x + 5 to justify the solution. What value of x is the solution?

x =