The average mark of of candidates in an aptitude test was 128.5 with deviation of 8.2. Three scores are extracted from the test are; 148,102,152. What is the average of the extracted scores that are extreme values?

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

30

step-by-step explanation:

idk

i hope i

answer: median

step-by-step explanation:

the median is the middle value when a data set is ordered from least to greatest

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation: