Find the Coordinates of a point A, where AB is diameter of a circle whose
centre is (2,-3) and B is (1,4)

(3, -10)

Step-by-step explanation:

let A(x,y) and B(x1,y1)=(1,4)

by midpoint formula i.e. (x+x1)/2 ; (y+y1)/2

as midpoint is centre so,

(2, -3) = (x+1)/2 ; (y+4)/2

2=(x+1)/2  and -3=(y+4)/2

4-1=x    and   -6-4=y

x=3       and    y=-10

therefore A(x,y)=A(3,-10)

your answer is b ^w^ hope i

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b