PLZ HELP! Joel rolls two fair number cubes at the same time. What is the probability that the sum of the numbers will be odd or less than 4? Show your work.

Joel rolls two fair number cubes at the same time.

Each cube has six sides 1, 2, 3, 4, 5, 6

=> There are 6 x 6 = 36 possible pairs (or 36 possible sums)

The collection of pairs that have sum less than 4 includes (1, 2), (2, 1) and (1, 1) => 3 cases (*)

The sum that is odd when two cubes show one odd number and one even number. Therefore each side of first cube has 3 options from second cube to form an odd sum. => The total number of cases: 6 x 3 = 18  cases

In these 18 cases, there are two cases (1, 2) and (2, 1) which have been counted already at (*) => Total case that the sum of the numbers will be odd or less than 4: T = 3 + 18 - 2 = 19 cases

=> Probability that the sum of the numbers will be odd or less than 4:

P = 19/36 = 0.53

Hope this helps!

:)

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.