Please answer correctly

No, x = -12/23 , y = -14/23

Step-by-step explanation:

Solve the following system:

{-3 x - 4 y = 4 | (equation 1)

y - 5 x = 2 | (equation 2)

Swap equation 1 with equation 2:

{-(5 x) + y = 2 | (equation 1)

-(3 x) - 4 y = 4 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{-(5 x) + y = 2 | (equation 1)

0 x - (23 y)/5 = 14/5 | (equation 2)

Multiply equation 2 by 5:

{-(5 x) + y = 2 | (equation 1)

0 x - 23 y = 14 | (equation 2)

Divide equation 2 by -23:

{-(5 x) + y = 2 | (equation 1)

0 x+y = (-14)/23 | (equation 2)

Subtract equation 2 from equation 1:

{-(5 x)+0 y = 60/23 | (equation 1)

0 x+y = -14/23 | (equation 2)

Divide equation 1 by -5:

{x+0 y = (-12)/23 | (equation 1)

0 x+y = -14/23 | (equation 2)

Collect results:

{x = -12/23 , y = -14/23

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry