What is the area of trapezoid DEFG with coordinates D (4, 3), E (4, 0), F (2, 1), and G (2, 3)? 10 square units
5 square units
3 square units
2 square units

5 square units

Step-by-step explanation:

Our coordinates are

D (4, 3), E (4, 0), F (2, 1), and G (2, 3)

Area of trapezoid= 1/2(a+b)h

Let's define our letters

a = base 1= 3-0=3

b = base 2 = 3-1= 2

h = height = 4-2= 2

Area = 1/2(3+2)2

Area= 1/2(5)2

Area = 5 square unit.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

answer: '

the distance between points l and m

step-by-step explanation: