Please help. 10 points and brainliest.

D

Step-by-step explanation:

since you can't divide by zero, you get a vertical asymptote (x=something) in effect

you can't divide by x+3

if x=-3, thus answers A and B are wrong

now lets look at the coefficients of 2/(x-3)

the horizontal asymptote of -1 exists in the rational equation D, since it is transformed down one unit, but has the same degrees in 2/(x+3), specifically, 1/1=1, thus we can use y=-1

here is a graph to prove everything

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.