Stephen is 2 years older than Sushil. krutika is 4 years younger than Sushil. If the total of their ages is 61, how old is the eldest of them?

Sushill's age = 21

Stephens age = 23

Krutika = 17

Step-by-step explanation:

You have to start somewhere, so let's call Sushill's ages as x.

Sushill's age = x

Stephens age = x +2

Krutika = x - 4

All x ages together is 61 so...

x + x + 2 + x - 4 = 61

3x - 2 = 61

3x = 61 + 2

x = 63/3

63/3 = 21 so now you know all ages because x = 21

Sushill's age = x

Stephens age = x +2

Krutika = x - 4

The answer is:

Sushill's age = 21

Stephens age = 23

Krutika = 17

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !