A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, determine which system of inequality best explains whether the company can build 20 child bikes and 6 adult bikes in the week. (2 points) A: No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 B: No, because the bike order does not meet the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100 C: Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 D: Yes, because the bike order meets the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100

A: No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100

Step-by-step explanation:

c = child bike

a = adult bike

Child bike requirement:

4 hours build time

4 hours test time

Adult bike requirement:

6 hours build time

4 hours test time

Available Building time per week ≤ 120 hours

Available Testing time per week ≤ 100 hours

Therefore, company's work schedule is;

Building:

4c + 6a ≤ 120

Testing:

4c + 4a ≤ 100

Combined:

4c + 6a ≤ 120 and 4c + 4a ≤ 100

Building 20 Child bike and 6 adult bike in a week:

4(20) + 6(6) ≤ 120 and 4(20) + 4(6) ≤ 100

80 + 36 ≤ 120 - - - - 80 + 24 > 100

Therefore Building 20 Child bike and 6 adult bike in a week is not feasible.

Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100

Step-by-step explanation:

I took the test on FLVS

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.