Let q = demand for seats on a 500-seat airplane and p = price charged per ticket. Suppose that q = 600 - 3p and assume that the unit cost of flying a passenger is $50. To maximize profit from the flight, the airline should charge how much per ticket?

Step-by-step explanation:

Given the equation  q = 600 - 3p where;

q = demand for seats on a 500-seat airplane

p = price charged per ticket

Revenue = demand for seats * price charged per ticket i.e pq

Revenue = p * 600 - 3p ... 1

Cost of flying a passenger = unit cost *  demand for seats = 50q

Cost of flying a passenger = 50q ...2

Profit generated will be the revenue less cost i.e Revenue - cost

Profit generated = p(600 - 3p) - 50q

= p(600 - 3p) - 50(600-3p)

= 600p-3p²-30000+150p

= -3p²+750p-30000

Profit P = -p²+250p-10000

To maximize the profit, dP/dp = 0

-2p+250 = 0

-2p = -250

p = $125

To maximize profit, the airline should charge $125 per ticket

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: