SAT verbal scores are normally distributed with a mean of 430 and a standard deviation of 120 (based on data from the College Board ATP). Solve each part of the equation.
(a) If a single student is randomly selected, find the probability that the sample mean is above
500.
(b) If a sample of 35 students are selected randomly, find the probability that the sample
mean is above 500.
(c)These two problems appear to be very similar. Which problem requires the application of
the central limit theorem, and in what way does the solution process differ between the two
problems?

answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

hope it !

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation: