Find the range of values for which
x2–5x + 6 < 0

here, we are required to find the range of values for which

The range of values for which x²–5x + 6 < 0

is at;x < 3

x2–5x + 6 < 0

By solving the expression quadratically; we have;

x² -3x -2x +6 < 0

By factorization;

(x - 2)(x - 3) < 0

Therefore;

The range of values for which x²–5x + 6 < 0

is at;

x < 3

Read more:

link

-2<x<3

or x∈(-2,3)

Step-by-step explanation:

x²-5x<-6

add (-5/2)² i.e.,25/4

x²-5x+25/4<-6+25/4

(x-5/2)²<(-24+25)/4

(x-5/2)²<1/4

(x-5/2)²<(1/2)²

|x-5/2|<1/2

-1/2<x-5/2<1/2

Add 5/2

-1/2+5/2<x-5/2+5/2<1/2+5/2

-2<x<3

step-by-step explanation:

b and c

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.