PLEASE HELP : A rectangle has a length that is 15 more than its width. A second rectangle with a perimeter of 72 has a width that is 5 wider and a length that is 2 shorter than the first rectangle. Find the dimensions of the first rectangle.

length = 24, width = 9

Step-by-step explanation:

Let's call the length and width of the first rectangle w + 15 and w respectively. This means that the length and width of the second rectangle is (w + 15) - 2 and w + 5 respectively. Since the perimeter of the second rectangle is 72, we can write:

2 * ((w + 15) - 2 + w + 5) = 72 because perimeter = 2 * (length + width)

(w + 15) - 2 + w + 5 = 36 (Divide by 2)

2w + 18 = 36 (Combine like terms)

2w = 18 (Subtract 18)

w = 9 (Divide by 2)

This means that the length and width are 24 and 9.

the answer is simply just 6n add the two together as they have an n

step-by-step explanation: