Consider the initial value problem y'' + 49 y = cos(7t), y(0) = 9, y'(0) = 6. a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). cos (7 t)/s^2 b. Solve your equation for Y(s). Y(s) = Laplace {y(t)}}= c. Take the inverse Laplace transform of both sides of the previous equation to solve for y(t). y(t) =

35/49/50

Step-by-step explanation:

3.5/7.8/4.9=50

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17