Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB

The distace between midpoints of AP and QB is .

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ =

QB =

Substituing:

AP + 2*() = a

2AP = a

AP =

Since the distance is between midpoints of AP and QB:

2QB = AP

QB =

QB =

QB =

MIdpoint is the point that divides the segment in half, so:

Midpoint of AP:

Midpoint of QB:

The distance is:

d =

d =

y=x+2 hope this jdjxhdnzbdjdo

the distance from any point on the parabola to the focus is the exact same as the distance from that point to the directrix.

if you could provide answer choices that might allow me to answer the question easier if my above answer isn't an option! (: