If a family has three children, then there are eight possible outcomes for the gender of the children (where F represents a female child and M represents a male child): S = {FFF, FFM, FMF, MFF, MMF, MFM, FMM, MMM} A three child family is selected at random. Assuming each of the eight above outcomes are equally likely, what is the probability that the randomly selected family has less than five male children?

i want to die

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d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

x=0

step-by-step explanation: