In two or more complete sentences describe why the range of y = cos(x) is -1 ≤ y ≤ 1. Make sure to reference the unit circle in your description.

Here's what I get  

Step-by-step explanation:

The range is the spread of the y-values (minimum to maximum).

cos x = adjacent/hypotenuse

In terms of the unit circle,

"adjacent" = x

"hypotenuse" = 1, so

cos x = the x-coordinate

Let's evaluate cos x as we go around the unit circle.

The function y = cos x starts at 1, then decreases smoothly through 0 at 90° to -1 at 180°.

It then increases smoothly through 0 at 270° to 1 at 360°, and the cycle repeats.

The minimum value is -1.

The maximum value is 1

The range is −1 ≤ y ≤ 1.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb