Help me answer this question please with full working

a. y = x^2 + 10

b. when x=5,   y  = 35

c. when y = 26,   x =  +4 or -4

Step-by-step explanation:

Given

y = k (x^2/2 + 5), and

(2,14) is on the curve.

Solution:

Substitute x=2 and y=14 in the above equation

14 = k (2^2/2 + 5)

14 = k (2+5)

14 = 7k

k = 14/7 = 2

a. equation connecting x and y is

   y = 2 (x^2/2 + 5), or

   y = x^2 + 10

b. when x=5

   y = 5^2 + 10 = 25 + 10 = 35

c. when y = 26

  26 = x^2 + 10

  x^2 = 26-10 = 16

  x= sqrt(16) = +4 or -4

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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