A repair shop repairs an average of 4.5 machines per hour. Let X be the time (in hours) before the first machine is repaired.(a) What is the probability that a repair time exceeds 4 hours?(b) What is the average time (in hours) it takes to repair the first machine?(c) The conditional probability that a repair takes at least 6 hours, given that it takes more than 4 hours?

a) P(X>4)=e-4*4.5 =1.523*10-8 ~ 0.0000

b) 1/4.5 =0..2222 Hours

c) P(X>6|X>4) =P(X>2)=e-2*4.5 =0.000123

Step-by-step explanation:

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median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all