Which polynomial functions have only the roots 1 and 4? Check all that apply.
f(x) = (x - 1)(x – 4)
f(x) = 3(x + 1)(x + 4)
f(x) =(4x - 1)(x – 4)
f(x) = 3(x - 1)(x – 4)
f(x) = 6(x - 1)(x-4)

Hey there!

Your answer would be f(x) = (x - 1)(x – 4),  3(x - 1)(x – 4), and 6(x - 1)(x-4) .

The polynomial roots can be found by finding the values of x that make the equation equal to 0. We know that when two items are multiplied, and one of them is zero, the result is 0. Thus, we have to make only one of the items equal to 0. To make the roots 1 and 4, we have to have (x-1) and (x-4).

4-4=0, x=4

1-1=0, x=1

A,D,E

second answer is : f(x) = (x – 3)(x – 3)(x – 6)

Step-by-step explanation:

got it right on edg2020

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step-by-step explanation:

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the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: